i1 = R = ZZ/101[a..d] o1 = R o1 : PolynomialRing
i2 = S = image map(R, R, {a^4, a^3*b, a*b^3, b^4}) o2 = S o2 : QuotientRing
i3 = presentation S o3 = | c3-bd2 ac2-b2d bc-ad b3-a2c | 1 4 o3 : Matrix R <--- R
i4 = h = hilbertPolynomial S 0 1 o4 = - 3 P + 4 P o4 : ProjectiveHilbertPolynomial
The rational quartic curve in P^3 is therefore 'like' 4 copies of P^1, with three points missing. One can see this by noticing that there is a deformation of the rational quartic to the union of 4 lines, or 'sticks', which intersect in three successive points.
These Hilbert polynomials can serve as Hilbert functions, too.
i5 = h 3 o5 = 13
i6 = basis(3,S) o6 = | a3 a2b a2c a2d ab2 abd acd ad2 b2d bd2 c2d cd2 d3 | 1 ZZ 13 o6 : Matrix S <--- (---) 101
i7 = rank source basis(3,S) o7 = 13
Note that the Hilbert polynomial of P^i is z |--> binomial(z + i, i).
See also ProjectiveHilbertPolynomial.
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